X^2=16x+336

Solution for X^2=16x+336 equation:

X^2=16X+336

We move all terms to the left:

X^2-(16X+336)=0

We get rid of parentheses

X^2-16X-336=0

a = 1; b = -16; c = -336;
Δ = b2-4ac
Δ = -162-4·1·(-336)
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-40}{2*1}=\frac{-24}{2}
=-12
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+40}{2*1}=\frac{56}{2}
=28
$